MATH SOLVE

3 months ago

Q:
# A man ate 100 bananas in five days, each day eating 6 more than the previous day. How many bananas did he eat on the first day?

Accepted Solution

A:

The number of bananas consumed by the man on first day is 8.
Solution:
Given that Number of bananas consumed by man = 100
Number of day in which bananas we consumed = 5
Also given that each day eating 6 more than the previous day
Need to calculate the number of bananas consumed on first day
Let us assume number of bananas consumed of first day = x
As it is given that each day, he eats 6 more than previous day,
So number of bananas consumed on second day = number of bananas consumed of first day + 6 = x + 6
Similarly number of bananas consumed on third day = [tex](x +6) + 6 = x + 12[/tex]Number of bananas consumed on fourth day = [tex](x + 12) + 6 = x + 18[/tex]Number of bananas consumed on Fifth day = [tex](x + 18) + 6 = x + 24[/tex]So total banana consumed in 5 days = [tex]x + (x + 6) + (x + 12) + (x + 18) + (x + 24)[/tex][tex]\Rightarrow[/tex] Total banana consumed in 5 days = [tex]5x + 60[/tex]But it’s given that total banana consumed in 5 days = 100
[tex]\Rightarrow 5 x+60=100[/tex]On solving above expression for x, we get
[tex]\begin{array}{l}{5 x=100-60} \\\\ {\Rightarrow x=\frac{40}{5}=8}\end{array}[/tex]Hence number of bananas consumed on first day is equal to 8.