Q:

The length of a rectangle is seven less than twice the length of its width. If the area of the rectangle is 15 square meters, find the value of x.​

Accepted Solution

A:
Length = 3mWidth = 5mState where x is accordingly.The length of a rectangle is seven less than twice the length of its width.L = 2W - 7A = W * LA = 1515 = W * LSubstitute the L in terms of W15 = W * (2W - 7)15 = 2W^2 - 7W2W^2 - 7W - 15 = 0Factorise:(2W + 3) (W - 5) = 0Solve for W:2W + 3 = 02W = 0 - 32W = 3W = 3/2W = 1.5W - 5 = 0W = 0 + 5W = 5Use the original equation to find L:L = 2W - 7L = 2(5) - 7L = 10 - 7L = 3L * W = 153 * 5 = 15